Cut command in Bash

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Eg of a Bash script that displays:
The content of the current directory
In a list format
Where only the part of the name after the first dash is displayed
list_dir=$(ls)
for i in $list_dir; do
echo "$i" | cut -d '-' -f2
done
The script uses the ls command to list the contents of the current directory and assigns the result to the list_dir variable.
Here's a breakdown of the script:
list_dir=$(ls): This line uses the command substitution syntax$(...)to execute thelscommand and store the result in thelist_dirvariable. Thelscommand lists the contents of the current directory.for i in $list_dir; do: This line starts theforloop. It iterates over each item in thelist_dirvariable. The loop variableitakes each value in each iteration.echo "$i" | cut -d '-' -f2: This line uses theechocommand to print the current value of the loop variablei. The|symbol is a pipe, which redirects the output of theechocommand to the input of thecutcommand.
The cut command is used to extract specific parts of a line or string based on a delimiter. Let's break down the command cut -d '-' -f2:
-d '-': This specifies the delimiter used to separate the fields in the input. In this case, the delimiter is set to-, meaning that the input will be split into fields whenever a-character is encountered.-f2: This specifies the field(s) to be extracted from the input. In this case, it is set to2, indicating that the second field after splitting the input on the delimiter will be extracted.
For example, let's consider the input string "example-text". Using the cut command with -d '-' -f2 on this input will result in "text" being extracted because:
The delimiter
-splits the input into two fields:"example"and"text".The
-f2option specifies that the second field, which is"text", should be extracted.
In the context of the script, the cut command is used to extract the part of the name after the first dash (-) in each item of the directory listing. It splits the input string at the first - character and returns the portion after it.



